Question : If $y+\frac{1}{y}=3$, then what is the value of $\frac{1}{y^3}+y^3 ?$
Option 1: 12
Option 2: 27
Option 3: 24
Option 4: 18
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 18
Solution : Use: Use the following formula to solve the question: $(y+\frac{1}{y})^3=y^3+\frac{1}{y^3}+3(y+\frac{1}{y})$ ⇒ $y^3+\frac{1}{y^3}=(y+\frac{1}{y})^3-3(y+\frac{1}{y})$ ⇒ $y^3+\frac{1}{y^3}=3^3-3×3$ ⇒ $\frac{1}{y^3}+y^3 = 18$ Hence, the correct answer is 18.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $x=p+\frac{1}{p}$ and $y=p-\frac{1}{p}$, then the value of $x^{4}-2x^{2}y^{2}+y^{4}$ is:
Question : If $\left(3 y+\frac{3}{y}\right)=8$, then find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Question : If $6^{x}=3^{y}=2^{z}$, then what is the value of $\frac{1}{y}+\frac{1}{z}-\frac{1}{x}$?
Question : What is the value of $\frac{4x^2+9y^2+12xy}{144}$?
Question : If $x^2+\frac{1}{x^2}=7$, then what is the value of $x^3+\frac{1}{x^3}$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile