Question : If $\left(w+\frac{1}{w}\right)=6$, then what will be the value of $\left(w-\frac{1}{w}\right)?$
Option 1: $4 \sqrt{2}$
Option 2: $\sqrt{2}$
Option 3: $3 \sqrt{2}$
Option 4: $2 \sqrt{2}$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $4 \sqrt{2}$
Solution : Given: $\left(w+\frac{1}{w}\right)=6$ Squaring both sides, we have, ⇒ $\left(w+\frac{1}{w}\right)^{2}=6^{2}$ ⇒ $w^{2}+\frac{1}{w^{2}}+2=36$ ⇒ $w^{2}+\frac{1}{w^{2}}=34$ ⇒ $w^{2}+\frac{1}{w^{2}}-2=34-2$ ⇒ $(w-\frac{1}{w})^{2}=32$ ⇒ $(w-\frac{1}{w})=\sqrt{32}$ $\therefore(w-\frac{1}{w})=4\sqrt{2}$ Hence, the correct answer is $4\sqrt{2}$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:
Question : If $\left(y^2+\frac{1}{y^2}\right)=74$ and $y>1$, then find the value of $\left(y-\frac{1}{y}\right)$.
Question : If $a=\frac{1}{a-\sqrt{6}}$ and $(a>0)$, then the value of $\left(a+\frac{1}{a}\right)$ is:
Question : If $\sin \theta \cos \theta=\frac{\sqrt{2}}{3}$,then the value of $\left(\sin ^6 \theta+\cos ^6 \theta\right)$ is:
Question : If $\left(x+\frac{1}{x}\right)=5 \sqrt{2}$, and $x>1$, what is the value of $\left(x^6-\frac{1}{x^6}\right) ?$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile