if v, p, and E denote the magnitude of velocity momentum and kinetic energy of the particle then
Answer (1)
Student Expert
27th Sep, 2019
Hello there!
Greetings!
Dimensions of momentum [P]=[MLT1][P]=[MLT1]
Dimensions of velocity [v]=[LT1][v]=[LT1]
Dimensions of energy [E]=[ML2T2]
Then,
P = dE/dv as ,
Dimensions of LHS of above equation =[MLT1]
Dimensions of RHS =ML2T2/LT1=MLT1.
LHS = RHS
Thankyou
Greetings!
Dimensions of momentum [P]=[MLT1][P]=[MLT1]
Dimensions of velocity [v]=[LT1][v]=[LT1]
Dimensions of energy [E]=[ML2T2]
Then,
P = dE/dv as ,
Dimensions of LHS of above equation =[MLT1]
Dimensions of RHS =ML2T2/LT1=MLT1.
LHS = RHS
Thankyou
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