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If V = x^2 - 5x + 4 , find the acceleration of the particle when velocity of the particle is zero

gaikwadomkar124 12th Aug, 2020

Answer (1)

Prabhav Sharma 12th Aug, 2020

Hello,

Velocity of the particle is given by, v = x^2 - 5x + 4 (Given)

Therefore, acceleration = dv/dt = d/dt(x^2 - 5x + 4)

= 2x * dx/dt - 5 * dx/dt

= 2x * v - 5 * v [We know, dx/dt = v]

When v = 0, Acceleration will be = 2x * 0 - 5 * 0 = 0

Therefore, Acceleration of the particle is 0 when velocity of the particle is 0 (Answer)

Hope it is clear!

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