Question : If $x^2-15 x+1=0$, what is the value of $x^4-223 x^2+6 ?$
Option 1: 9
Option 2: 5
Option 3: 6
Option 4: 0
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Answer (1)
25th Jan, 2024
Correct Answer: 5
Solution :
$x^2-15 x+1=0$
$⇒x^2+1=15 x$
$⇒(x^2+1)^{2}= (15x)^{2}$
$⇒x^4+2x^2+1= 225x^2$
$⇒x^4-223x^2 = –1$
Adding 6 on both sides, we get,
So, $x^4-223 x^2+6 = –1+6 = 5$
Hence, the correct answer is 5.
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