Question : If $m^n=169$, what is the value of $(m+1)^{n-1}$?
Option 1: 14
Option 2: 13
Option 3: 196
Option 4: 170
Answer (1)
23rd Jan, 2024
Correct Answer: 14
Solution :
Given:
$m^n=169$
⇒ $m^n=13^2$
So, $m=13, n=2$
Now, $(m+1)^{n-1}$
= $(13+1)^{2-1}$
= $(14)^{1}$
= $14$
Hence, the correct answer is 14.
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