x^2.y^3=(x+y)^5
Or, 2x.y^3+3y^2.x.(dy/dx)=5(x+y)^4.(1+(dy/dx))
Or, 3y^2.x(dy/dx)_5(x+y)^4.(dy/dx)=5(x+y)^4_2x.y^3
Or,(dy/dx)=[5(x+y)^4_2x.y^3][3y^2.x_5(x+y)^4]


This is the answer of your question.
:)

=Hi ShubhamKumar,

The solution of the question : If x2y3 =(x+y)5 then find the dy/dx is mention below:

ð ((2x)( y^3))dx+3((x^2)(y^2))dy=5dx+5dy
ð x((2x).(y^3)-5)=dy(5-((3x^2)(y^2)))
dy/dx=(2x.(y^3)-5)/ (5-((3x^2)(y^2)))