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Hello Arjun,
The JEE Main Paper 2 results is annou nced on 31 st January. NTA has provided a criteria of percentage score this year. You can take help from the previous year cutoff marks
MNIT Jaipur – Rank 77 to Rank 1738
MNIT Bhopal – Rank 74 to Rank 1928
MNIT Calicut – Rank 50 to Rank 1834
MNIT Hamirpur – Rank 91 to Rank 2325
NIT Patna –Rank 78 to Rank 4153
NIT Rourkela – Rank 28 to 1712
NIT Trichy – Rank 10 to 1931
VNIT Nagpur – Rank 45 to 1952
Hope this helps.
Hello arjun,
Congratulations for your performance
Total number of students appeared for jee main 2 paper id 180000.
So you can calculate your rank by this method:
180000×(100- obtained percentile)/100
By this your rank would be around 34000.
Good luck
Candidates can download NATA Question/Sample papers from here for better preparation.
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