Question : In a 7-digit number 89476*2, what is the smallest possible value of * such that the number is divisible by 8?
Option 1: 2
Option 2: 1
Option 3: 4
Option 4: 3
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : For a number to be divisible by 8, the last 3 digits should be divisible by 8. In the given number 89476*2, the last 3 digits are 6*2. Since we have to find the smallest number with the given condition, we start substituting * with 0 to 9 and check if it is divisible by 8. 602 is not divisible by 8. 612 is not divisible by 8. 622 is not divisible by 8. 632 is divisible by 8. Hence, the correct answer is 3.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : An 11-digit number 7823326867X is divisible by 18. What is the value of X?
Question : If the four-digit number 463y is divisible by 7, then what is the value of y?
Question : A six-digit number is divisible by 33. If 54 is added to the number, then the new number formed will also be divisible by:
Question : If a nine-digit number 789x6378y is divisible by 72, then the value of xy is:
Question : If the 8-digit number 123456xy is divisible by 8, then the total possible pairs of (x, y) are:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile