Question : In a $\triangle $ABC, the bisector of $\angle $B and $\angle $C meet at O in the triangle. If $\angle $BOC = 134º, then the measure of $\angle $A is:
Option 1: 116º
Option 2: 104º
Option 3: 52º
Option 4: 88º
Correct Answer: 88º
Solution : As BO and CO are the angle bisectors of $\angle $B and $\angle $C respectively. ⇒ $\triangle $BOC = 90º + $\frac{1}{2}\angle $A ⇒ 134º = 90º + $\frac{1}{2}\angle $A ⇒ $\angle $A = 2 × 44º = 88º Hence, the correct answer is 88º.
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Question : In a $\triangle \mathrm{ABC}$, the bisectors of $\angle \mathrm{B}$ and $\angle \mathrm{C}$ meet at $\mathrm{O}$. If $\angle \mathrm{BOC}=142^{\circ}$, then the measure of $\angle \mathrm{A}$ is:
Question : Internal bisectors of $\angle$ B and $\angle$ C of $\triangle$ ABC meet at O. If $\angle$ BAC = $80^{\circ}$, then the value of $\angle$ BOC is:
Question : In $\triangle$ABC, $\angle$A = 66°. AB and AC are produced at points D and E, respectively. If the bisectors of $\angle$CBD and $\angle$BCE meet at the point O, then $\angle$BOC is equal to:
Question : In a $\triangle ABC$, the bisectors of $\angle$ABC and $\angle$ACB intersect each other at point O. If the $\angle$BOC is 125°, then the $\angle$BAC is equal to:
Question : In $\triangle \mathrm{ABC}, \angle \mathrm{A}=54^{\circ}$. If I is the incentre of the triangle, then the measure of $\angle \mathrm{BIC}$ is:
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