3 Views

Question : In a $\triangle P Q R, \angle P=90^{\circ}, \angle R=47^{\circ}$ and $P S \perp Q R$. Find the value of $\angle Q P S$.

Option 1: 43°

Option 2: 47°

Option 3: 45°

Option 4: 40°


Team Careers360 18th Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 47°


Solution :

In a $\triangle P Q R, $
$\angle P=90^{\circ}$
$\angle R=47^{\circ}$
$P S \perp Q R$
$\angle PSR = 90^{\circ}$
In $\triangle PSR, $
$\angle R + \angle PSR + \angle RPS = 180^{\circ}$
$47^{\circ} + 90^{\circ} + \angle RPS = 180^{\circ}$
$\angle RPS = 180^{\circ}-137^{\circ}=43^{\circ}$
$\angle P=\angle RPS+\angle QPS$
$90^{\circ} = 43^{\circ}+\angle QPS$
$\angle QPS= 47^{\circ}$
Hence, the correct answer is $47^{\circ}$.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
GRE ® Registrations 2024
Apply
Apply for GRE® Test now & save 10% with ApplyShop Gift Card | World's most used Admission Test for Graduate & Professional Schools
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books