Question : In a bag, the number of INR 5 coins is 8 more than the number of INR 10 coins but 20% less than the number of INR 2 coins. If the total amount in the bag is INR 270, what is the number of INR 5 coins?
Option 1: 15
Option 2: 20
Option 3: 25
Option 4: 18
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Correct Answer: 20
Solution : Let's assume the number of INR 2, INR 5 and INR 10 coins are 'a', 'b', and 'c' respectively. In a bag, the number of INR 5 coins is 8 more than the number of INR 10 coins but 20% less than the number of INR 2 coins. ⇒ b = c + 8 ⇒ c = (b – 8) ⇒ b = (100 – 20)% of a ⇒ b = 80% of a ⇒ b = 0.8a ⇒ a = $\frac{b}{0.8}$ The total amount in the bag is INR 270. We can write this as: ⇒ 2a + 5b + 10c = INR 270 ⇒ 2 × $\frac{b}{0.8}$ + 5b + 10 × (b - 8) = 270 ⇒ 2.5b + 5b + 10b - 80 = 270 ⇒ 17.5b = 350 ⇒ b = 20 Therefore, the number of INR 5 coins is 20. Hence, the correct answer is 20.
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