Question : In a bag, there are coins of INR 2, INR 5 and INR 10 denominations. The total number of coins in the bag is 300. If the number of coins of INR 2, INR 5 and INR 10 denominations are in the ratio of 1 : 2 : 3, then what is the total amount of money in the bag?
Option 1: INR 2,100
Option 2: INR 2,500
Option 3: INR 3,000
Option 4: INR 2,400
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Correct Answer: INR 2,100
Solution : Let the number of coins of INR 2, INR 5, and INR 10 denominations be $x,2x$, and $3x$, respectively. The total number of coins is given as 300. ⇒ $x + 2x+ 3x = 300$ ⇒ $x = \frac{300}{6}= 50$ Number of INR 2 coins $=x=50$ Number of INR 5 coins $= 2x = 2 × 50 = 100$ Number of INR 10 coins $= 3x = 3 × 50 = 150$ So, the total amount = (2 × number of INR 2 coins) + (5 × number of INR 5 coins) + (10 × number of INR 10 coins) = (2 × 50) + (5 × 100) + (10 × 150) = 100 + 500 + 1500 = 2100 Hence, the correct answer is INR 2,100.
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