Question : In a circle, chords AB and CD intersect internally at E. If CD = 18 cm, DE = 5 cm, AE = 13 cm, then the length of BE is:
Option 1: 4 cm
Option 2: 7 cm
Option 3: 3 cm
Option 4: 5 cm
Correct Answer: 5 cm
Solution : Given: CD = 18 cm, DE = 5 cm, AE = 13 cm Now, CE = CD – DE = 18 – 5 = 13 cm Let the length of BE be $x$. According to the concept, $\Rightarrow AE\ \times BE\ =\ CE\ \times DE$ $\Rightarrow 13\ \times x\ =\ 13\ \times 5$ $\Rightarrow x\ =\ 5$ cm Hence, the correct answer is 5 cm.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : Chords AB and CD of a circle intersect externally at P. If AB = 6 cm, CD = 3 cm, and PD = 5 cm, then the length of PB is:
Question : Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Question : AB is a chord in a circle of radius 13 cm. From centre O, a perpendicular is drawn through AB intersecting AB at point C. The length of OC is 5 cm. What is the length of AB?
Question : In a given circle, the chord PQ is of length 18 cm. AB is the perpendicular bisector of PQ at M. If MB = 3 cm, then the length of AB is:
Question : In a circle of radius 5 m, AB and CD are two equal and parallel chords of length 8 m each. What is the distance between the chords?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile