Question : In a circle with centre $O$ and diameter $E F$, if the two chords $A E=A F$, then $ \angle A E F$ is:
Option 1: 80°
Option 2: 90°
Option 3: 45°
Option 4: 60°
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 45°
Solution :
In a circle with centre O and diameter EF, if the two chords AE = AF, then they form an isosceles triangle.
Also, we know that the angle in a semicircle is 90°.
$⇒\angle EAF = 90°$
Let $\angle AEF = \angle AFE = x$
Since the sum of angles in a triangle is 180°.
$⇒x+x+\angle EAF = 180°$
$⇒2x+90° = 180°$
$⇒2x=90°$
$⇒x=45°$
So, $\angle AEF = 45°$
Hence, the correct answer is 45°.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.