In a class 60% pass in finance . among those passed in finance , 33 1/3% passed in marketing . 150 failed in both subjects . 1/3rd of students who passed in marketing failed in finance. 1 how many students are there in class? 2 what percentage of students failed in finance only?

Hello,

firstly, lets denote:

F as the number of students who passed in finance,

M as the number of students who passed in marketing,

B as the number of students who passed in both subjects,

X as the total number of students in the class.

Given:

60% pass in finance----   F = 60X/100= 0.6X

Among those passed in finance, 33 1/3% passed in marketing:  M = 0.333F = 0.333(0.6X)

150 failed in both subjects: B = 150

1/3rd of students who passed in marketing failed in finance:  0.333M = 1/3* (0.6X - B)

To find the number of students in the class:

B = 0.333F + 0.667M - B

B = 0.333(0.6X) + 0.667(0.333(0.6X)) - 150

B = 0.2X + 0.133X - 150

B = 0.333X - 150

150 = 0.333X - B

150 = 0.333X - 150

300 = 0.333X

X= 300/0.333

X= 90(approx)

So, there are approximately 900 students in the class.

Now, to find the percentage of students who failed in finance only, we need to find the number of students who failed in finance but passed in marketing.

Failed in finance only=  0.6X - B

Failed in finance only= 0.6(900) - 150

Failed in finance only = 540 - 150

Failed in finance only= 390

To find the percentage, divide by the total number of students and multiply by 100:

Percentage of students who failed in finance only= (390/900)*100%

Percentage of students who failed in finance only= 43.33%

So, approximately 43.33% of students failed in finance only.

Hope this helps,

Thank you