in a compound microscope the magnified virtual image is formed at a distance of 25cm from the eyepiece
Answer (1)
28th Jul, 2021
Hello aspirant,
In a compound microscope if a magnified virtual image is produced at a distance of 25 cm from the eye-piece and the focal length of its objective lens is 1 cm and the magnification is 100 with the tube length of the microscope as 20 cm, the focal length of the eyepiece lens (in cm) will be:-
Given,
L = 20, f0 = 1cm, M = 100
We know,
M= (v0/u0)(1+(D/f))
or, M= (L/f0)(1+(D/f))......[as, v0 ≈L, u0≈f0]
or, 100= (20/1)(1+(25/f))
on solving we get
f = 6.25 cm...........(Ans.)
Hope this helps,
All the Best!!
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