Question : In a linear race of 1000 m, Prakash beats Ved by 280 m, while Ved beats Rahul by 100 m. By how many metres does Prakash beat Rahul, in the same race?
Option 1: 346
Option 2: 350
Option 3: 352
Option 4: 348
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 352
Solution : Given: In a linear race of 1000 m, Prakash beats Ved by 280 m, while Ved beats Rahul by 100 m. Prakash beats Ved by 280 m, So, ratio of distances by Prakash : Ved = 1000 : (1000 – 280) = 1000 : 720 = 125 : 90 Also, Ved beats Rahul by 100 m. So, ratio of distances by Ved : Rahul = 1000 : (1000 – 100) = 1000 : 900 = 10 : 9 = 90 : 81 Therefore, ratio of distances by Prakash : Ved : Rahul = 125 : 90 : 81 = 1000 : 720 : 648 $\therefore$ Prakash beats Rahul by (1000 – 648) = 352 m in a race of 1000 m. Hence, the correct answer is 352.
Candidates can download this e-book to give a boost to thier preparation.
Answer Key | Eligibility | Application | Admit Card | Preparation Tips | Result | Cutoff
Question : In a 120-metre race, P beats S by 6 metres. If S starts with ahead start of 7.5 metres and it is a 100-metre race, then who wins the race and how many metres? (Correct to 2 decimal places)
Question : In a 1 km race P completes the race in 120 seconds and Q in 125 seconds. The distance by which P beats Q is:
Question : A missile travels at 1386 km/hr. How many metres does it travel in one second?
Question : What is the distance between the hurdles in 100 m women's hurdles in metres?
Question : If the sides of an equilateral triangle are increased by 1 metre, then its area is increased by $\sqrt3$ sq. metre. The length of any of its sides is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile