In a PMDC motor, when armature is rotated at 100rpm, an emf of 2V is developed across its terminals. For this motor, calculate the armature current flow required to generate a torque of 0.4Nm.
Answer (1)
26th Oct, 2020
Required torque (T) = 0.4 Nm
Eb = 2V
Mechanical Power delivered = P = T*w = Eb* Ia
Eb=back emf
Ia = Amateur current
w = Angular frequency
w = 2pi * n /60 = 2pi*100/ 60 = 10.47 rad/seconds
from the previous equation
Ia = T*w/Eb = 0.4 * 10.472 / 2 = 2.0944 A
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