Question : In a $\triangle$PQR, the side QR is extended to S. If $\angle$QPR = 72° and $\angle$PRS=110°, then the value of $\angle$PQR is:
Option 1: 38°
Option 2: 32°
Option 3: 25°
Option 4: 29°
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Correct Answer: 38°
Solution : Given: $\angle$QPR = 72° and $\angle$PRS = 110° An exterior angle of a triangle is equal to the sum of the two opposite interior angles. So, $\angle PQR + \angle QPR =\angle PRS$ ⇒ $\angle PQR + 72° = 110°$ ⇒ $\angle PQR = 110° - 72° = 38°$ Hence, the answer is 38°.
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Question : S and T are points on the sides PQ and PR, respectively, of $\triangle$PQR such that PS × PR = PQ × PT. If $\angle$Q = 96° and $\angle$PST = $\angle$PRQ + 34°, then $\angle$QPR = ?
Question : In $\triangle {PQR} $, PQ = PR and S is a point on QR such that $\angle {PSQ}=96^{\circ}+\angle {QPS}$ and $\angle {QPR} = 132^{\circ}$. What is the measure of $\angle {PSR}$?
Question : In a cyclic quadrilateral ABCD, the side AB is extended to a point X. If $\angle XBC=82°$ and $\angle ADB=47°$, then the value of $\angle BDC$ is:
Question : If $ABC \cong PQR$ and $\angle ABC = (x + 60)°$, $\angle PQR = (85 – 4x)°$, and $\angle RPQ = (3x + 65)°,$ then the value of $\angle ABC$ in degree is:
Question : $PQR$ is a triangle, whose area is 180 cm2. $S$ is a point on side $QR$ such that $PS$ is the angle bisector of $\angle QPR$. If $PQ: PR = 2:3$, then what is the area (in cm2) of triangle $PSR$?
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