1 View

Question : In a trapezium ABCD, AB and DC are parallel sides and $\angle ADC=90^\circ$. If AB = 15 cm, CD = 40 cm and diagonal AC = 41 cm, then the area of the trapezium ABCD is:

Option 1: 245 cm2

Option 2: 240 cm2

Option 3: 247.5 cm2

Option 4: 250 cm2


Team Careers360 15th Jan, 2024
Answer (1)
Team Careers360 17th Jan, 2024

Correct Answer: 247.5 cm 2


Solution :
In trapezium ABCD, $\angle ADC = 90^\circ$, AB = 15 cm, DC = 40 cm and AC = 41 cm.
In $\Delta ADC$,
AC 2 = AD 2 + DC 2
⇒ 41 2 = AD 2 + 40 2
⇒ 1681= AD 2 + 1600
⇒ AD = 9 cm
The area of the trapezium = $\frac{1}{2}$ × (40 + 15) × (9) = 247.5 cm 2
Hence, the correct answer is 247.5 cm 2 .

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books