Question : In a triangle ABC a straight line parallel to BC intersects AB and AC at D and E, respectively. If AB = 2AD, then DE : BC is:
Option 1: 2 : 3
Option 2: 2 : 1
Option 3: 1 : 2
Option 4: 1 : 3
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Correct Answer: 1 : 2
Solution : AB = 2AD As $\triangle$ADE ~ $\triangle$ABC, ⇒ $\frac{\text{AD}}{\text{AB}}$ = $\frac{\text{DE}}{\text{BC}}$ ⇒ $\frac{1}{2}$ = $\frac{\text{DE}}{\text{BC}}$ ⇒ $\frac{\text{DE}}{\text{BC}}$ = $\frac{1}{2}$ Hence, the correct answer is 1 : 2.
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Question : In a $\triangle$ABC, DE||BC, D and E lie on AB and AC, respectively. If AB = 7 cm and BD = 3 cm, then find BC : DE.
Question : In $\triangle$ABC, the bisector of $\angle$BAC intersects BC at D and the circumcircle of $\triangle$ABC at E. If AB : AD = 3 : 5, then AE : AC is:
Question : In triangle ABC, DE $\parallel$ BC where D is a point on AB and E is a point on AC. DE divides the area of $\Delta ABC$ into two equal parts. Then BD : AB is equal to:
Question : In $\triangle$ABC, D and E are points on AB and AC, respectively, such that DE || BC and DE divide the $\triangle$ABC into two parts of equal areas. The ratio of AD and BD is:
Question : If D and E are the mid-points of AB and AC respectively of $\triangle$ABC then the ratio of the areas of $\triangle$ADE and square BCED is:
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