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Question : In a triangle $PQR$, $QR$ is produced to $S$. If $\angle PRS=(9x-15^{\circ}), \angle RPQ=2x$ and $\angle PQR = (4{x}+15^{\circ})$, what is the value of $x$?

Option 1: 55

Option 2: 20

Option 3: 10

Option 4: 75


Team Careers360 23rd Jan, 2024
Answer (1)
Team Careers360 24th Jan, 2024

Correct Answer: 10


Solution :
Given: $\angle PRS=(9x-15^{\circ}), \angle RPQ=2x$ and $\angle PQR=(4{x}+15^{\circ})$
Applying exterior angle property, we get:
$\angle PRS=\angle RPQ+\angle PQR$
⇒ $(9x-15^{\circ}) = 2x+(4{x}+15^{\circ})$
⇒ $3x=30^{\circ}$
⇒ $x=10^{\circ}$
Hence, the correct answer is 10.

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