Question : In $\triangle {ABC} $, AB = 48 cm, BC = 55 cm and AC = 73 cm. If O is the centroid of the triangle, then the length (in cm) of BO (correct to one decimal place) is:
Option 1: 25.6
Option 2: 24.3
Option 3: 20.4
Option 4: 18.3
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 24.3
Solution : Since 48, 55, and 73 are triplets $\triangle ABC$ is a right-angled triangle and $\angle B = 90^\circ$ We know that in a right-angled triangle, Length of the median from the right-angled vertex = $\frac{\text{Length of hypotenuse}}{2}$ ⇒ $BM = \frac{AC}{2} = \frac{73}{2}$ And we know that OB : OM = 2 : 1 $\therefore OB = \frac{2}{3} × \frac{73}{2}= 24.33$ cm Hence, the correct answer is 24.3.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : G is the centroid of a triangle ABC, whose sides AB = 35 cm, BC = 12 cm, and AC = 37 cm. The length of BG is (corrected to one decimal place):
Question : Triangle ABC and DEF are similar. If AB = 92 cm, BC = 48 cm, AC =120 cm, and the length of the smallest side of triangle DEF is 200 cm, then find the length of the longest side of triangle DEF.
Question : In a triangle ${ABC}, {AB}={AC}$ and the perimeter of $\triangle {ABC}$ is $8(2+\sqrt{2}) $ cm. If the length of ${BC}$ is $\sqrt{2}$ times the length of ${AB}$, then find the area of $\triangle {ABC}$.
Question : $\triangle ABC$ is a triangle. PQ is a line segment intersecting AB in P and AC in Q and PQ || BC. The ratio of AP : BP = 3 : 5 and the length of PQ is 18 cm. The length of BC is:
Question : $\triangle ABC$ is an isosceles triangle with AB = AC = 15 cm and an altitude from A to BC of 12 cm. The length of side BC is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile