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Question : In $\triangle ABC$, $\angle B = 90^{\circ}$, AB = 8 cm and BC = 15 cm, then $\sin C$?

Option 1: $\frac{15}{17}$

Option 2: $\frac{8}{17}$

Option 3: $\frac{15}{8}$

Option 4: $\frac{8}{15}$


Team Careers360 3rd Jan, 2024
Answer (1)
Team Careers360 24th Jan, 2024

Correct Answer: $\frac{8}{17}$


Solution :
By Pythagoras theorem,
AC = $\sqrt{8^2 + 15^2}$
= $\sqrt{64 + 225}$
= $\sqrt{289}$
= 17 cm
⇒ $\sin$ C = $\frac{8}{17}$
Hence, the correct answer is $\frac{8}{17}$.

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