Question : In $\triangle$ABC, $\angle$A = 90°, AD$\perp$BC and AD = BD = 2 cm. The length of CD is:
Option 1: 3 cm
Option 2: 3.5 cm
Option 3: 3.2 cm
Option 4: 2 cm

Question

Question : Suppose $\triangle ABC$ be a right-angled triangle where $\angle A=90°$ and $AD\perp BC$. If the area of $\triangle ABC =40$ cm$^{2}$ and $\triangle ACD =10$ cm$^{2}$ and $\overline{AC}=9$ cm, then the length of $BC$ is:

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Answer 1

Correct Answer: 2 cm

Solution :
Given:
AD = BD = 2 cm
$\angle$A = 90°
AD is perpendicular to BC.
In $\triangle$ABC right angled at A, a perpendicular AD is drawn at BC then AD ² = BD × CD
∴ 2 ² = 2 × CD
⇒ CD = 2 cm
Hence, the correct answer is 2 cm.

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Question : In $\triangle$ABC, $\angle$A = 90°, AD$\perp$BC and AD = BD = 2 cm. The length of CD is:Option 1: 3 cmOption 2: 3.5 cmOption 3: 3.2 cmOption 4: 2 cm

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Question : In $\triangle$ABC, $\angle$A = 90°, AD$\perp$BC and AD = BD = 2 cm. The length of CD is:
Option 1: 3 cm
Option 2: 3.5 cm
Option 3: 3.2 cm
Option 4: 2 cm