Question : In an equilateral triangle STU, inradius is $5 \sqrt{3 }\mathrm{~cm}$. What is the length of the side of this equilateral triangle?
Option 1: $20 \sqrt{3} \mathrm{~cm}$
Option 2: $18 \sqrt{3} \mathrm{~cm}$
Option 3: $30 \mathrm{~cm}$
Option 4: $24 \mathrm{~cm}$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: $30 \mathrm{~cm}$
Solution :
In an equilateral triangle, the inradius (r) is related to the side length ($a$) by,
$ a = 2\sqrt{3}r $
Given that the inradius, $r=5\sqrt{3}$ cm,
$⇒a = 2\sqrt{3} \times 5\sqrt{3} = 2 \times 15 = 30 \text{ cm} $
Hence, the correct answer is $30 \mathrm{~cm}$.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
