Question : In an examination, the average marks of a student per paper were 71. If he had obtained 35 more marks in sciences; 11 more marks in history and 4 more marks in computer science, his average marks per paper would have been 76. How many papers were there in the examination?
Option 1: 10
Option 2: 12
Option 3: 18
Option 4: 15
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Correct Answer: 10
Solution : Average marks of a student per paper = 71 Let $n$ be the number of papers. Total marks scored = $71n$ New average = 76 New total = $76n$ ⇒ $71n + 35 + 11 + 4 = 76n$ ⇒ $5n = 50$ ⇒ $n = 10$ Hence, the correct answer is 10.
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