Question : In an office, there are 108 tables and 132 chairs. If $\frac{1}{6}$th of the tables and $\frac{1}{4}$th of the chairs are broken, how many people can work in the office if each person requires one table and one chair?
Option 1: 86
Option 2: 90
Option 3: 92
Option 4: 99
Correct Answer: 90
Solution :
Given:
Number of tables = 108
Number of chairs = 132
Broken tables = $\frac{1}{6}$th of total tables = $\frac{108}{6}$ = 18
Broken chairs = $\frac{1}{4}$th of total chairs = $\frac{132}{4}$ = 33
According to the question,
Undamaged tables = total tables – broken tables = 108 – 18 = 90
Undamaged chairs = total chairs – broken chairs = 132 – 33 = 99
There are 90 undamaged tables and 99 undamaged chairs.
So only 90 pairs of tables and chairs can be used by people as per the question.
Hence, the correct answer is 90.
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