Question : In an office, there are 108 tables and 132 chairs. If $\frac{1}{6}$th of the tables and $\frac{1}{4}$th of the chairs are broken, how many people can work in the office if each person requires one table and one chair?
Option 1: 86
Option 2: 90
Option 3: 92
Option 4: 99
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 90
Solution : Given: Number of tables = 108 Number of chairs = 132 Broken tables = $\frac{1}{6}$th of total tables = $\frac{108}{6}$ = 18 Broken chairs = $\frac{1}{4}$th of total chairs = $\frac{132}{4}$ = 33 According to the question, Undamaged tables = total tables – broken tables = 108 – 18 = 90 Undamaged chairs = total chairs – broken chairs = 132 – 33 = 99 There are 90 undamaged tables and 99 undamaged chairs. So only 90 pairs of tables and chairs can be used by people as per the question. Hence, the correct answer is 90.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : Six tables and twelve chairs were bought for Rs. 7,800. If the average price of a table is Rs. 750, then the average price of a chair would be:
Question : What is the Highest Common Factor of $\frac{3}{8}$ and $\frac{4}{9}$?
Question : What is the value of $\frac{\left[\left(\frac{5}{7} \text { of } \frac{1}{12} \times \frac{1}{4}-\frac{1}{2} \times \frac{1}{8}\right)+\frac{5}{4} \times \frac{8}{15}-\frac{2}{3}\right]}{\frac{1}{2} \div \frac{1}{4}+\frac{1}{2}}$ ?
Question : If $x=-1$, then the value of $\frac{1}{x^{99}}+\frac{1}{x^{98}}+\frac{1}{x^{97}}+\frac{1}{x^{96}}+\frac{1}{x^{95}}+\frac{1}{x^{94}}+\frac{1}{x}-1$ is:
Question : In a college, $\frac{1}{5}$th of the girls and $\frac{1}{8}$th of the boys took part in a social camp. The part of students in the college who took part in the camp are:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile