2217 Views

in fraunhofer diffraction pattern slit width is 0.2mm and screen is at 2m away from the lens if wavelength of light used is 5000A then the distance between the first minimum on either side of the central maximum is


Vaishnavi Shirke 19th Apr, 2020
Answer (1)
Smrity 19th Apr, 2020

Hey,

We know that,

the distance between the first 2 minimum of either side of the central maximum is equal to 2 lambda D/ d

where,

it is given that,

d=0.2mm

D= 2 m

lambda=5000A

is,

= (2*5*10^3*10^-10*2)/(2*10^-1*10^-3)

=10*(10^-7/10^-4)

=10^-2 m

which is the required answer.

I hope this helps.

All the best!

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida M.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
SCSVMV Deemed to be Universit...
Apply
MBA At at SCSVMV | NAAC 'A' Grade | AICTE & UGC Aproved | 100% Placement Support | Merit-based Scholarships
Amity University-Noida BBA Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
RV University, Mysuru | B.Tec...
Apply
World-class and highly qualified engineering faculty. High-quality global education at an affordable cost
New Horizon College BBA Admis...
Apply
UG Admissions 2026 open| NAAC ‘A’ grade | Merit-based Scholarships available.
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books