Question : In $\triangle \mathrm{ABC}, \angle \mathrm{A}=68^{\circ}$. If I is the incentre of the triangle, then the measure of $\angle B I C$ is:
Option 1: 124°
Option 2: 68°
Option 3: 148°
Option 4: 54°
Correct Answer: 124°
Solution :
In $\triangle ABC$,
$\angle A = 68^{\circ}$
$\angle BIC = 90^{\circ} + \frac{\angle A}{2}$
$= 90^{\circ} + \frac{68^{\circ}}{2}$
$= 90^{\circ} + 34^{\circ}$
$= 124^{\circ}$
Hence, the correct answer is $124^{\circ}$.
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