In JEE MAINS 2020 I got 96.555 percentile. General category. Can I get a seat in any good NIT? I am from Kolkata.
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Hi'
Congratulations for your remarkable performance in jee!
It’s difficult to tell you the exact about your admission possibilities but as per the previous year cutoff as a general category the chance seems less to get a seat in NITs, however you can try for IIITs & GFTIs and state counseling like Punjab, Haryana, MP, Etc. To know your admission chances in JOSSA & State counseling you can use JEE Main college Predictor tool.
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answ er
All the best!
All things apart i would first like to congratulate you over your remarkable performance. You have scored a very good percentile. Your rank will be under 30,000 but the concerning thing here will be that it would be quite tough path for you to get into any top NITs with this rank for any preferable branch. But i would like to suggest you to start studying for the JEE Advanced but you can also take one more shot in the next attempt in the April session. I am adamant that you can easily secure 99 percentile in your second attempt and you can even do great JEE advanced.
Wish you good luck for future endeavours.
Kindly calculate your rank with the formula
(100 - your total score) X 869010 /100.
Where 100 is your total percentile score is the percentage of people ahead of you
869010 are the number of candidates appeared for january exam. So through this your rank can be known here is the previous year cut offs for different institutes
https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches/amp
Check it there .
And I will post the college predictor link too so that you would get an idea
https://engineering.careers360.com/jee-main-college-predictor
All the best
Dear Aspirant,
Your percentile is quite good but you can give your best in April attempt and defenietly acheive more percentile then January session .
A formula is given by nta to caclulate rank .The formula is no of candidates apperared in exam/100*(100- Nta score ).
So according to this formula your rank will be
29937.
You can also use college predictor to check chances of getting admiited in particular Colleges -
Thanks
All the very best
You can calculate your rank in JEE Main Paper 1 using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 1 (Jan) are around 869000, your rank will be around 30000. However as the no. of students in April changes, your rank will change according to that.
With this rank, there are less chances of getting a good branch at one of the top NITs but you may get some another NITs with this rank.
However, since state quota applies for NIT Durgapur, you have high chances of getting into NIT Durgapur.
You can check last years' cutoffs using the link given:
https://josaa.nic.in/webinfocms/Public/View.aspx?page=71
To predict the colleges which you may get with this percentile, kindly use the college predictor through the link provided below:
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