Question : In $\triangle$PQR, $\angle$ PQR = $90^{\circ}$, PQ = 5 cm and QR = 12 cm. What is the radius (in cm) of the circumcircle of $\triangle$PQR?
Option 1: 6.5
Option 2: 7.5
Option 3: 13
Option 4: 15
Correct Answer: 6.5
Solution :
In $\triangle$ PQR, $\angle$ PQR = $90^{\circ}$, PQ = 5 cm and QR = 12 cm
PR
2
= PQ
2
+ QR
2
$PR = \sqrt{5^2 + 12^2} = \sqrt{25+144} = \sqrt{169} = 13$ cm
Circumradius of $\triangle PQR = \frac{PR}{2} = \frac{13}{2} = 6.5$ cm
Hence, the correct answer is 6.5.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
