Question : In the figure, chords AB and CD of a circle intersect externally at P. If AB = 4 cm, CD = 11 cm and PD =15 cm, then the length of PB is:
Option 1: 10 cm
Option 2: 8 cm
Option 3: 14 cm
Option 4: 12 cm
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Correct Answer: 10 cm
Solution : AB and CD are two chords of a circle intersecting externally at P AB = 4 cm, CD = 11 cm and PD = 15 cm If two chords AB and CD intersect at outer point P then, PA × PB = PC × PD Let the length of PA be $x$ PC = PD - CD = 15 - 11 = PC = 4 cm According to the question PA × PB = PC × PD ⇒ $x$ × ($x$ + 4) = 15 × 4 ⇒ $x$ = 6 PB = PA + AB = 6 + 4 = 10 $\therefore$ The length of PB is 10 cm. Hence, the correct answer is 10 cm.
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