in the following eqns determine for what value of k if any will the system having 1.unique solution,2.no solution,3.infinite solutions. Kx+2y=3 ,2x-4y=-6
Answer (1)
6th Dec, 2020
Hi Candidate,
The following equation is of the type- Kx+ 2y=3 and the second equation is - 2x-4y= -6. So, as we know that for unique solution Condition, k/2=2/-4, so for unique solution, k=-1.
Now for No solution Condition, k2 is not equal to 2/-4, so k is not equal to -1. For infinite solutions condition, we have the condition that- k/2= 2/-4= 3/-6, so the value of k= -1.
Hope that this answer helps you.
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