Question : In the following figure, O is the centre of the circle. Its two chords AB and CD intersect each other at point P inside the circle. If AB =18 cm, PB = 6 cm, and CP = 4 cm, then find the measure of PD.
Option 1: 14 cm
Option 2: 18 cm
Option 3: 16 cm
Option 4: 20 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 18 cm
Solution :
Given: Two chords AB and CD intersect each other at point P inside the circle.
AB =18 cm, PB = 6 cm and CP = 4 cm
AP = AB – PB
= 18 – 6 = 12 cm
According to the formula,
AP × PB = CP × PD
⇒ 12 × 6 = 4 × PD
⇒ PD = 3 × 6 = 18 cm
Hence, the correct answer is 18 cm.
Related Questions
Question : In the given figure, the diameter AB and chord CD of a circle meet at P. PT is tangent to the circle at T. If CD = 8 cm, PD = 10 cm, and PB = 8 cm, find AB.
Question : AB and CD are two chords in a circle with centre O and AD is a diameter. AB and CD produced meet a point P outside the circle. If $\angle A P D=25^{\circ}$ and $\angle D A P=39^{\circ}$, then the measure of $\angle C B D$ is:
12 Views
Question : AB and CD are two chords in a circle with centre O and AD is a diameter. AB and CD produced meet a point P outside the circle. If $\angle A P D=25^{\circ}$ and $\angle D A P=39^{\circ}$, then the measure of $\angle C B D$ is:
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
