Question : In the given figure, $\angle ABC=81^{\circ}$ and $\angle ACB=9^{\circ}$. What is the value of $\angle BDC$?
Option 1: 80°
Option 2: 90°
Option 3: 70°
Option 4: 60°
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Correct Answer: 90°
Solution : The angles at the circumference subtended by the same arc are equal. In $\triangle ABC$, $\angle ABC + \angle BCA + \angle ACB = 180°$ ⇒ $81° + 9° +\angle BAC= 180°$ ⇒ $\angle BAC = 90°$ Now, $\angle BAC = \angle BDC = 90°$ (Angle made by the same arc on the same side of the circle are equal) Hence, the correct answer is 90°.
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Question : Directions: Select the option figure in which the given figure is embedded as its part (rotation is NOT allowed).
Question : Directions: Select the figure that will come next in the following figure series.
Question : In the given figure, ' $G$ ' is the centre of the circle. Find the $\angle ACB$ when $\angle AGB=132^{\circ}$.
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