Question : 
In the given figure, ' $G$ ' is the centre of the circle. Find the $\angle ACB$ when $\angle AGB=132^{\circ}$.
Option 1: $62^{\circ}$
Option 2: $66^{\circ}$
Option 3: $64^{\circ}$
Option 4: $60^{\circ}$
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Correct Answer: $66^{\circ}$
Solution :
Given: $\angle AGB=132^{\circ}$.
$\angle AGB= 2×\angle ACB$ [$\because$Angle subtended by an arc at the centre is twice the angle subtended by the same arc at the circumference of the circle on the same side]
⇒ $132^{\circ}= 2×\angle ACB$
⇒ $\angle ACB=66^{\circ}$
Hence, the correct answer is $66^{\circ}$.
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