Question : In the given figure, ' $G$ ' is the centre of the circle. Find the $\angle ACB$ when $\angle AGB=132^{\circ}$.
Option 1: $62^{\circ}$
Option 2: $66^{\circ}$
Option 3: $64^{\circ}$
Option 4: $60^{\circ}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $66^{\circ}$
Solution : Given: $\angle AGB=132^{\circ}$. $\angle AGB= 2×\angle ACB$ [$\because$Angle subtended by an arc at the centre is twice the angle subtended by the same arc at the circumference of the circle on the same side] ⇒ $132^{\circ}= 2×\angle ACB$ ⇒ $\angle ACB=66^{\circ}$ Hence, the correct answer is $66^{\circ}$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : In the given figure, $\mathrm{O}$ is the centre of the circle and $\angle\mathrm{AOB}=130^{\circ}$. Find $\angle\mathrm{APB}$.
Question : In the given figure, $\angle ABC=81^{\circ}$ and $\angle ACB=9^{\circ}$. What is the value of $\angle BDC$?
Question : In the given figure, PQRS is a square and SRT is an equilateral triangle. What is the value of $\angle SOR ?$
Question : In the given figure, the measure of $\angle A$ is:
Question : Directions: Select the option figure in which the given figure is embedded as its part (rotation is NOT allowed).
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile