Question : In the given figure, O is the centre of the circle, $\angle PQO=30^{\circ}$ and $\angle QRO=45^{\circ}$. What is the value (in degrees) of $\angle POR$?
Option 1: $150^{\circ}$
Option 2: $110^{\circ}$
Option 3: $160^{\circ}$
Option 4: $130^{\circ}$
Correct Answer: $150^{\circ}$
Solution : Given: $\angle PQO=30^{\circ}$ and $\angle QRO=45^{\circ}$ Since $OQ$ and $OR$ is the radius, So, $\angle OQR=45^{\circ}$ $⇒\angle POR=2(\angle PQO+\angle OQR)$ (By angle subtended by minor arc.) $\therefore \angle POR=2(30^{\circ}+45^{\circ})=2×75^{\circ}=150^\circ$ Hence, the correct answer is $150^\circ$.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : In the adjoining figure $\angle AOC=140^{\circ}$, where O is the centre of the circle then $\angle ABC$ is equal to:
Question : In the given figure, O is the centre of the circle, $\angle DAB=110^{\circ}$ and $\angle BEC=100^{\circ}$. What is the value (in degrees) of $\angle OCB$? 3 Views
Question : In the following figure, AB is the diameter of a circle whose centre is O. If $\angle AOE=150^{\circ},\angle DAO=51^{\circ}$ then the measure of $\angle CBE$ is:
Question : In the given figure, O is the centre of the circle, $\angle PQR=100^{\circ}$ and $\angle STR=105^{\circ}$. What is the value (in degree) of $\angle OSP$?
4 Views
Question : Direction: The pie chart shows the breakup of the monthly expenditure of a person.
What is the central angle made by the sector of expenditure on
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile