Question : In the given figure, point O is the centre of a circle of radius 13 cm and AB is a chord perpendicular to OD. If CD = 8 cm, what is the length (in cm) of AB?
Option 1: 6 cm
Option 2: 12 cm
Option 3: 24 cm
Option 4: 28 cm
Correct Answer: 24 cm
Solution :
Given, Radius = 13 cm
CD = 8 cm
⇒ OC = 13 – 8 = 5 cm [As OD is the radius]
In $\triangle AOC$,
Using Pythagoras theorem, we get,
$AO^2=OC^2+AC^2$
⇒ $13^2=5^2+AC^2$
⇒ $AC^2=169-25$
⇒ $AC=\sqrt{144}$
$\therefore AC = 12$ cm
Now, $AB = 2\times AC= 2\times 12 = 24$ cm
Hence, the correct answer is 24 cm.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
