1 View

Question : In trapezium $ABCD$, $AB \parallel CD$ and $AB = 2CD$. Its diagonals intersect at $O$. If the area of $\triangle AOB=84\;\mathrm{cm^2}$ then the area of $\triangle COD$ is equal to:

Option 1: 72 cm2

Option 2: 21 cm2

Option 3: 42 cm2

Option 4: 26 cm2


Team Careers360 13th Jan, 2024
Answer (1)
Team Careers360 20th Jan, 2024

Correct Answer: 21 cm 2


Solution :

In trapezium $ABCD$, $AB \parallel CD, AB = 2CD$ and area of $\Delta AOB=84\;\mathrm{cm^2}$.
In $\triangle AOB$ and $\triangle COD$,
$\angle AOB=\angle COD$ (Vertically opposite angles)
$\angle ABO=\angle CDO$ (Alternate angles)
$\angle BAO=\angle DCO$ (Alternate angles)
So, $\triangle AOB\sim\triangle COD$
Using the theorem, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
$\frac{\operatorname{Area of }\Delta AOB}{\operatorname{Area of }\Delta COD}=\frac{AB^2}{CD^2}$
⇒ $\frac{84}{\operatorname{Area of }\Delta COD}=\frac{4CD^2}{CD^2}=4$
⇒ $\operatorname{Area of }\triangle COD=21$ cm 2
Hence, the correct answer is 21 cm 2 .

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
GRE ® Registrations 2024
Apply
Apply for GRE® Test now & save 10% with ApplyShop Gift Card | World's most used Admission Test for Graduate & Professional Schools
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books