Question : In triangle ABC, AD BE and CF are the medians intersecting at point G and the area of triangle ABC is 156 cm2. What is the area (in cm2) of triangle FGE?
Option 1: 13
Option 2: 26
Option 3: 39
Option 4: 52
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 13
Solution : AD, BE and CF are the median intersecting at point G $\therefore$ Area of joining the points D, E and F would be $\frac{1}{4}$th of $\triangle ABC$ Area of of $\triangle DEF=\frac{1}{4}\times156=39 \;cm^2$ G will be the centroid of the triangle. Area of $\triangle FGE$ = Area of $\triangle DFG$ = Area of $\triangle DGE$ = $\frac{1}{3}$ Area of $\triangle DEF$ = $\frac{1}{3}\times 39$ = $13 \ cm^2$ Hence, the correct answer is 13.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If $AD, BE$ and $CF$ are medians of $\triangle ABC$, then which of the following statement is correct?
Question : The hypotenuse of a right-angled triangle is 39 cm and the difference of the other two sides is 21 cm. Then, the area of the triangle is:
Question : The sides of a triangle are 20 cm, 21 cm, and 29 cm. The area of the triangle formed by joining the midpoints of the sides of the triangle will be:
Question : If in triangle ABC, MN is parallel to BC, and M and N are points on AB and AC respectively. The area of quadrilateral MBCN = 130 cm2. If AN : NC = 4 : 5, then the area of triangle MAN is:
Question : What is the area of a rhombus whose diagonals are 8 cm and 13 cm?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile