Question : In triangle MNO, AB is parallel NO and MA = 2.5, AN = 7.5, MB = 2.2, find the value of BO.
Option 1: 6.6
Option 2: 8.2
Option 3: 5.4
Option 4: 4.8
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 6.6
Solution :
Given:
In triangle MNO, AB is parallel NO and MA = 2.5, AN = 7.5, MB = 2.2
Here, triangles MNO and MAB are similar because angle M in triangle MNO is equal to angle M in triangle MAB.
So, $\frac{MA}{MN}=\frac{MB}{MO}$
⇒ $\frac{2.5}{2.5+7.5}=\frac{2.2}{MO}$
$\therefore MO=8.8$
BO = MO – MB = 8.8 – 2.2 = 6.6
Hence, the correct answer is 6.6.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Answer Key | Eligibility | Application | Admit Card | Preparation Tips | Result | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.