Question : $\triangle A B C$ inscribe in a circle with centre O. If AB = 9 cm, BC = 40 cm, and AC = 41 cm, then what is the circum-radius of the triangle?
Option 1: $20 \frac{1}{2} \mathrm{~cm}$
Option 2: $12 \frac{1}{2} \mathrm{~cm}$
Option 3: $18 \frac{1}{2} \mathrm{~cm}$
Option 4: $16 \frac{1}{2} \mathrm{~cm}$
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $20 \frac{1}{2} \mathrm{~cm}$
Solution : Given: $\triangle A B C$ inscribe in a circle with centre O. AB = 9 cm, BC = 40 cm, and AC = 41 cm Also, we can see $9^2+40^2=1681=41^2$ So, it is a right triangle. Hypotenuse = AC = 41 cm For any right-angled triangle, Circumradius $= \frac{1}{2} \times \text{Hypotenuse}= \frac{1}{2} \times 41= \frac{41}{2} = 20\frac{1}{2}\ \text{cm}$ Hence, the correct answer is $20\frac{1}{2}\ \text{cm}$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Question : An arc of length $33 \pi\;\mathrm{cm}$ subtends an angle of $132^\circ$ at the centre of the circle. Find the radius of the circle.
Question : A 9 cm long perpendicular is drawn from the centre of the circle to a 24 cm long chord. Find the radius of the circle.
Question : The area of a circle whose radius is the diagonal of a square whose area is $4\;\mathrm{cm^2}$ is:
Question : $\triangle\mathrm{ABC}$ is a right angled triangle. $\angle \mathrm{A}=90°$, $AB = 4$ cm, and $BC = 5$ cm. What is the value of $\cos B + \cot C$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile