integration of x square root of (4-x)/(4+x)dx
Answer (1)
24th Dec, 2019
Hello,
Please find the solution:
We are to evaluate, ∫x(x+4)12⋅dx .
We shall accomplish this by substitution.
Let,
(x+4)=t
⇒dx=dt
(By simple differentiation).
Thus, the integral becomes,
∫x(x+4)12⋅dx=∫t−4t12⋅dt
=∫t12⋅dt−∫4t−12⋅dt
=23t32−8t12+C , where C is the integration constant.
In terms of x , the integral may be now written as,
∫x(x+4)12⋅dx=23(x+4)32−8(x+4)12+C
Hope this helps, Good Luck.
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