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Hello Shikhar,
First of all congratulations on that score. Now, let me tell you about the probable rank that your percentile score might be able to fetch you. Since approximately around 145386 students appeared for JEE B. Arch exam so the rank can be predicted from the given formula -
(100- your total percentile score) * 1,45,386/ 100.
So, accordingly, your rank is somewhere around 8723 - 8724 when calculated with the percentile given by you. But, this is a rough evaluation so it is best that you wait till the final rank list is announced by NTA. Along with the result of JEE Main Paper-2 April session, authorities will also release the rank list.
For more details about the colleges that you might get, you can go through the following link which gives you previous year opening and closing ranks of various colleges-
Https://engineering.careers360.com/articles/jee-main-paper-2-result
Good luck!
Dear aspirant,
According to your score, your rank will be nearly (100-94)*145386/100=8722.You have less chances to get admission to get into an NIT according to previous year cutoffs.To know previous year cutoff, go to
Https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp
Know your college admission chances in NITs, IIITs and CFTIs, many States/ Institutes based on your JEE Main result by using JEE Main 2025 College Predictor.
Hello Shikhar
Congrats for scoring 94 percentile in JEE main paper 2.
We can't say that what NIT you wil get but we can predict the rank with this percentile .
There is a pedicted formula from our team to predict rank
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