Question : $\triangle ABC$ is a right angled triangle, $\angle B$ = 90°, $AB$ = 12 cm, $BC$ = 5 cm. What is the value of $\cos A + \sin C$?
Option 1: $\frac{24}{13}$
Option 2: $\frac{25}{13}$
Option 3: $\frac{10}{13}$
Option 4: $\frac{12}{13}$
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{24}{13}$
Solution : In $\triangle$ABC, ⇒ $AC$ 2 = $AB$ 2 + $BC$ 2 ⇒ $AC$ 2 = 12 2 + 5 2 ⇒ $AC$ = 13 cm $\cos A =\frac{\text{Base}}{\text{Hypotenuse}}=\frac{12}{13} $ $\sin C =\frac{\text{Perpendicular}}{\text{Hypotenuse}}=\frac{12}{13} $ Therefore, the value of cos A + sin C, $\therefore \cos A + \sin C =\frac{12}{13}$ + $\frac{12}{13}=\frac{24}{13} $ Hence, the correct answer is $ \frac{24}{13}$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : $\triangle{ABC}$ is a right angled triangle. $\angle \mathrm{C}=90°$, AB = 25 cm and BC = 20 cm. What is the value of $\mathrm{sec}\; A$?
Question : $\triangle\mathrm{ABC}$ is a right angled triangle. $\angle \mathrm{A}=90°$, $AB = 4$ cm, and $BC = 5$ cm. What is the value of $\cos B + \cot C$?
Question : $\triangle $KLM is a right-angled triangle. $\angle$M = 90$^{\circ}$, KM = 12 cm and LM = 5 cm. What is the value of $\sec$ L?
Question : Let $ABC$ and $PQR$ be two congruent right-angled triangles such that $\angle A=\angle P=90^{\circ}$. If $BC=13\ \text{cm}$ and $PR=12\ \text{cm}$, then find the length of $AB$.
Question : $\triangle PQR$ is a right-angled triangle. $\angle Q = 90^\circ$, PQ = 12 cm, and QR = 5 cm. What is the value of $\operatorname{cosec}P+\sec R$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile