Question : $\triangle ABC$ is an isosceles triangle with AB = AC. If $\angle BAC=50^\circ$, then the degree measure of $\angle ABC$ is equal to:
Option 1: $70^\circ$
Option 2: $55^\circ$
Option 3: $60^\circ$
Option 4: $65^\circ$
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Correct Answer: $65^\circ$
Solution :
Given: $\triangle ABC$ is an isosceles triangle with AB = AC.
$\angle BAC=50^\circ$
We know that the other two angles are the same in an isosceles triangle.
Let the other two angles be $x$.
The sum of the angles of a triangle is $180^\circ$
So, $50^\circ+x+x=180^\circ$
⇒ $2x=130^\circ$
$\therefore x=65^\circ$
Hence, the correct answer is $65^\circ$.
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